SOLUTION: Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number. 11x + 3 – 13x – 7 < 2(5 + 4x)

Algebra ->  Inequalities -> SOLUTION: Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number. 11x + 3 – 13x – 7 < 2(5 + 4x)       Log On


   

Question 164936:
Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number.
11x + 3 – 13x – 7 < 2(5 + 4x)

Found 2 solutions by checkley77, ptaylor:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
11x+3–13x–7<2(5+4x)
-3x-4<10+8x
-3x-8x<10+4
-11x<14
x>14/-11 dividing by a negative value changes the < sign to a > sign.
x>-14/11
Proof:
Let x=-13/11
11*-13/11+3-13*-13/11-7<2(5+4*-13/11)
-13+3+169/11-7<2(5-52/11)
-17+169/11<10-104/11
-17+15.3636<10-9.4545
-1.6364<-.5454

Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number.
11x + 3 – 13x – 7 < 2(5 + 4x)
Collect on the left side and get rid of parens (distributive law)

-2x-4<10+8x subtract 8x from and add 4 to each side
-2x-8x-4+4<10+4+8x-8x collect on both sides
-10x<14 divide each side by -10 (Note: the inequality sign changes)
x>-1.4 ---------------------------------------ans
Hope this helps----ptaylor