SOLUTION: {{{X plus 8/4-1>x/3}}}. I tried to answer it by multiplying by the recipricals of the equation. When I did that, I got {{{x+8-1>x}}}. Then I subtracted the 1 and got {{{x+7>x}}}. A

Algebra ->  Inequalities -> SOLUTION: {{{X plus 8/4-1>x/3}}}. I tried to answer it by multiplying by the recipricals of the equation. When I did that, I got {{{x+8-1>x}}}. Then I subtracted the 1 and got {{{x+7>x}}}. A      Log On


   



Question 156822This question is from textbook Glencoe Algebra 2
: X+plus+8%2F4-1%3Ex%2F3. I tried to answer it by multiplying by the recipricals of the equation. When I did that, I got x%2B8-1%3Ex. Then I subtracted the 1 and got x%2B7%3Ex. After that,I subtracted 7 from both sides. When I did, I got x%3E-7 as my answer. I don't know if that is right. This question is from textbook Glencoe Algebra 2

Found 2 solutions by nerdybill, Earlsdon:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
I think your expression is:
%28x%2B8%29%2F4-1%3Ex%2F3
.
If so, start by multiplying both sides by a common denominator (12):
3%28x%2B8%29-12+%3E+4x+
3x%2B24-12+%3E+4x+
3x%2B12+%3E+4x+
+12+%3E+x+

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
%28x%2B8%29%2F4+-1+%3E+x%2F3 Multiply both sides by 3.
%283x%2B24%29%2F4+-+3+%3E+x Mu;tiply both sides by 4.
3x%2B24-12+%3E+4x Simplify.
3x%2B12+%3E+4x Subtract 3x from both sides.
12+%3E+x or x+%3C+12