SOLUTION: Hi Tutors:
I am so lost over this one. Please help me:
Find the intersection point (if there is one) and graph shading the appropriate areas:
x+y >=0 and 2x+y<=4
Algebra ->
Inequalities
-> SOLUTION: Hi Tutors:
I am so lost over this one. Please help me:
Find the intersection point (if there is one) and graph shading the appropriate areas:
x+y >=0 and 2x+y<=4
Log On
Question 14138: Hi Tutors:
I am so lost over this one. Please help me:
Find the intersection point (if there is one) and graph shading the appropriate areas:
x+y >=0 and 2x+y<=4 Answer by longjonsilver(2297) (Show Source):
You can put this solution on YOUR website! intersection point is where the 2 equations are the SAME...they are equal at that point... the (x,y) of one equation is the same as the (x,y) of the other.
so, we have
x+y = 0 and
2x+y = 4
ignore the < and > for now...we are interested in where they ARE equal.
so sub 1 equation into the other and solve. Find the other variable afterwards.
Sketch the graph then... look at my lessons on sketching linear equations and also anything i have on inequalities too.
