SOLUTION: If |x + 1| <= 3, then a <= 1/(x + 5) <= b. Find a and b.

Algebra ->  Inequalities -> SOLUTION: If |x + 1| <= 3, then a <= 1/(x + 5) <= b. Find a and b.       Log On


   



Question 1208929: If |x + 1| <= 3, then a <= 1/(x + 5) <= b.
Find a and b.

Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
If |x + 1| <= 3, then a <= 1/(x + 5) <= b.
Find a and b.
~~~~~~~~~~~~~~~~~~~~~~~~~


        The formulation of the problem in the post is incorrect.

        The correct formulation is  " find the maximum a and the minimum b such that a <= 1/(x+5) <= b. "

        Or even simpler: "Find the range of the expression 1%2F%28x%2B5%29".

        Below is the solution for this modified formulation.


If  |x+1| <= 3,  it means that

    -3 <= x+1 <= 3.    (1)


Add 4 to each of the 3 sides of this compound inequality.
You will get then

    1 <= x+5 <= 7.     (2)



Consider left part of the compound inequality (2)

    1 <= x+5.          (3)


Right side of (3) is positive, so we can divide both sides of (3) by (x+5).
You will get then

    1%2F%28x%2B5%29 <= 1.      (4)



Next consider right part of the compound inequality (2)

    x+5 <= 7.          (5)


Right side of (5) is positive, so we can divide both sides of (5) by 7*(x+5).
You will get then 

     1%2F7 <= 1%2F%28x%2B5%29.    (6)



From  (4)  and  (6)  we get the final  ANSWER

    1%2F7 <= 1%2F%28x%2B5%29 <= 1.    


So,  a = 1%2F7;  b = 1.

Solved  (in the right modified formulation).

When solving and explaining, my task was to perform only necessary
calculations and explanations, without making unnecessary work.



Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


The prescribed values for x are defined by

abs%28x%2B1%29%3C=3
-3%3C=x%2B1%3C=3
-4%3C=x%3C=2

The interval of x values is thus [-4,2].

For all the values of x in that interval, x+5 is positive, so 1/(x+5) is positive and monotonically decreasing. So the maximum value of 1/(x+5) on [-4,2] is at the left end of the interval and the minimum value is at the right end of the interval.

ANSWERS:

a = minimum value = 1/(2+5) = 1/7
b = maximum value = 1/(-4+5) = 1/1 = 1