SOLUTION: An object is launched from ground level directly upward at a rate of 144
feet/sec. The equation for object’s height is
2
y x x = − + 16 144
. What values of x is the
objec
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-> SOLUTION: An object is launched from ground level directly upward at a rate of 144
feet/sec. The equation for object’s height is
2
y x x = − + 16 144
. What values of x is the
objec
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Question 1196168: An object is launched from ground level directly upward at a rate of 144
feet/sec. The equation for object’s height is
2
y x x = − + 16 144
. What values of x is the
object at or above a height of 288 feet? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An object is launched from ground level directly upward at a rate of 144
feet/sec. The equation for object’s height is
2
y x x = − + 16 144
. What values of x is the
object at or above a height of 288 feet?
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h(t) = -16t^2 + 144t is a usable equation.
-16t^2 + 144t = 288
t^2 - 9t + 18 = 0
(t-3)*(t-6) = 0
t = 3 and t = 6 seconds
