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| Question 1142546:  hello i have been working on this question for a while but I keep getting so confuse with what i have been writing on my piece of paper.
 Kyle works at a donut factory, where a 10-oz cup of coffee costs 95cents, a 14-oz cup costs $1.15, and a 20-oz cup costs $1.50. During one busy period, Kyle served 31 cups of coffee, using 484 ounces of coffee, while collecting a total of $38.80. How many cups of each size did Kyle fill?
 Found 2 solutions by  josmiceli, ankor@dixie-net.com:
 Answer by josmiceli(19441)
      (Show Source): Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! Kyle works at a donut factory, where a 10-oz cup of coffee costs 95cents,
 a 14-oz cup costs $1.15,
 and a 20-oz cup costs $1.50.
 During one busy period, Kyle served 31 cups of coffee, using 484 ounces of coffee, while collecting a total of $38.80.
 How many cups of each size did Kyle fill?
 :
 let a = no. of 10 oz cups
 let b = no. of 14 oz cups
 let c = no. of 20 oz cups
 :
 You can use the matrix feature on you calc to solve this
 1  1  1  31
 10 14 20 484
 .95 1.15 1.5 38.8
 :
 A more tedious method using elimination
 write an equation for each statement
 a + b + c = 31
 10a + 14b + 20c = 484 oz
 .95a + 1.15b + 1.50c = $38.80
 :
 multiply the 1st equation by 10, subtract from the 2nd equation
 10a + 14b + 20c = 484
 10a + 10b + 10c = 310
 -------------------------eliminates a, give us a 2 unknown equation
 0 + 4b + 10c = 174
 then
 multiply the 1st equation by .95, subtract from the 3rd equation
 .95a + 1.15b + 1.50c = 38.80
 .95a + .95b + .95c = 29.45
 -----------------------------eliminates a, another 2 unknown equation
 0 + .2b + .55c = 9.35
 multiply by 20, subtract the 1st 2 unknown eq
 4b + 11c = 187
 4b + 10c = 174
 -----------------subtraction eliminates b, find c
 0 + c = 13 ea 20 oz cups
 then
 4b + 11(13) = 187
 4b + 143 = 187 - 143
 4b = 187 - 143
 4b = 44
 b = 44/4
 b = 11 ea 14 oz cups
 then
 a + 11 + 13 = 31, you can find the 10 oz cups
 :
 I check my solutions using the matrix feature on my Ti83
 
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