SOLUTION: Prove that is a > b and c > d, then a + c > b + d.
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Question 1135110
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Prove that is a > b and c > d, then a + c > b + d.
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Prove that
if a > b and c > d, then a + c > b + d.
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a > b --> a = b+k for some k>0
c > d --> c = d+m for some m>0
a+c = (b+k)+(d+m) = (b+d)+(k+m) > b+d, QED.