SOLUTION: The fuel efficiency for a certain midsize car is given by E(v) = −0.016v2 + 1.376v + 3.8 where E(v) is the fuel efficiency in miles per gallon for a car traveling v mil

Algebra ->  Inequalities -> SOLUTION: The fuel efficiency for a certain midsize car is given by E(v) = −0.016v2 + 1.376v + 3.8 where E(v) is the fuel efficiency in miles per gallon for a car traveling v mil      Log On


   



Question 1129340: The fuel efficiency for a certain midsize car is given by
E(v) = −0.016v2 + 1.376v + 3.8
where
E(v)
is the fuel efficiency in miles per gallon for a car traveling v miles per hour.
(a) What speed will yield the maximum fuel efficiency? Round to the nearest mile per hour.______mph
(b) What is the maximum fuel efficiency for this car? Round to the nearest mile per gallon.____mpg

Found 2 solutions by rothauserc, josmiceli:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
E(v) = -0.016v^2 + 1.376v + 3.8
:
this is the equation of a parabola that curves downward
:
velocity is plotted along the x-axis and fuel efficiency is plotted along the y-axis
:
here is a graph of E(v)
:
+graph%28+300%2C+200%2C+-20%2C+100%2C+-20%2C+40%2C+-0.016x%5E2+%2B1.376x+%2B3.8%29+
:
from the graph, we see that the coordinates of the vertex will give us the answers to the questions a and b
:
a. The speed(v) that will yield the maximum fuel efficiency is found from the formula
:
v = -b/2a, where b and a are from the general form for a quadratic
:
ax^2 +bx +c
:
v = -1.376/(2(-0.016)) = 43
:
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speed for maximum fuel efficiency is 43 mph
*******************************************
:
b. substitute for v in the equation
:
E(v) = -0.016v^2 + 1.376v + 3.8
:
E(v) = -0.016(43)^2 + 1.376(43) + 3.8 = 33.384 is approximately 33
:
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The maximum fuel efficiency for the car is 33 miles per gallon
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:

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for the v-value of the vertex is:
+v%5Bmax%5D+=+-b%2F%282a%29+ where
+a+=+-.016+
+b+=+1.376+
+v%5Bmax%5D+=+-1.376%2F%282%2A%28-.016%29%29+
+v%5Bmax%5D+=+43+
(a)
43 mi/hr gives maximum fuel efficiency
(b)
+E%2843%29+=+-.016%2A43%5E2+%2B+1.376%2A43+%2B+3.8+
+E%2843%29+=+-.016%2A1849+%2B+59.168+%2B+3.8+
+E%2843%29+=+-29.584+%2B+62.968+
+E%2843%29+=+33.384+
The maximum fuel efficiency for the car is 33 mi/gal
( check my math )
------------------
Here's the plot of the equation:
+graph%28+400%2C+400%2C+-10%2C+100%2C+-10%2C+50%2C+-.016x%5E2+%2B+1.376x+%2B+3.8+%29+