Question 1107766: pleasw help me solve this. give the constraints and inequality of the problem below.mrs peralta needs to buy chairs and desks. a chair costs 120 and a desk costs 360.let x and y be the number of chairs and desks respectively. the budget is less than 16000. there are at least 50 chairs and at there are most 10 desks. graph and give three possible feasible solutions
Found 2 solutions by Boreal, stanbon:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 120x+360y<16,000
you can use 10 desks, and that is 3600
therefore, 120x+3600< 16000
120x<12400
x<104
(103, 10) would work, and frankly, since the budget is a maximum and not a required maximum, (102, 10) would also work and any number x between 50 and 103 with desks being 10.
If desks were 5
120x<16000-1800=14200
x<119
(118, 5) would work and any x greater than 50 and less than 119 would work.
A graph would include 0 desks (since no lower constraint) and 132 chairs.
It would also include 103, 10, since that is a maximum, and 118, 5.
Other points would include 50 chairs and 0 desks and 50 chairs and 1-10 desks as well
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! mrs peralta needs to buy chairs and desks. a chair costs 120 and a desk costs 360.let x and y be the number of chairs and desks respectively. the budget is less than 16000. there are at least 50 chairs and at there are most 10 desks. graph and give three possible feasible solutions
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120x + 360y < 16000
x >= 50
0<= y <=10
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Draw a vertical line at x = 50
Draw a horizontal line at y = 10
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Graph y = (-1/3)x + 44.4 as a dashed line.
Note:: If y = 10, x = 103
Other vertices are (50,0) ; (50,10) ; (133,0)
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Check each of those 4 vertices in 120x+360y to find the maximum combination
of chairs and desks.
Cheers,
Stan H.
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