SOLUTION: please let me know if I setup this problem correctly. The sum of three consecutive even integers is less than or equal to 126. Find the greatest values of the integers. X+y+z

Algebra ->  Inequalities -> SOLUTION: please let me know if I setup this problem correctly. The sum of three consecutive even integers is less than or equal to 126. Find the greatest values of the integers. X+y+z      Log On


   

Question 109655This question is from textbook
: please let me know if I setup this problem correctly.
The sum of three consecutive even integers is less than or equal to 126. Find the greatest values of the integers.
X+y+z_<126. Answer-- X<40, y<42, z<44
This question is from textbook

Found 2 solutions by checkley71, MathLover1:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X+X+2+X+4<=126
3X+6<=126
3X<=126-6
3X<=120
X<=120/3
X<=40 ANSWER FOR THE SMALLER NUMBER.
40+2=42
40+4=44

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

let x be 1st consecutive even integer
y=x%2B2 be 2nd consecutive even interger
z=x%2B4 be 3rd consecutive even integer
then:
x+%2B+y+%2B+z+%3C=+126
x%2B%28x%2B2%29%2B%28x%2B4%29%3C=126
3x+%2B+6+%3C=+126........move 6 to the right
3x+%3C=+126+-+6
3x+%3C=+120.....divide both sides by 3
x+%3C=+40........ 1st consecutive even integer
y+=+42.......2nd consecutive even interger
z+=+44.........2nd consecutive even interger