Let the larger be x, then the smaller is 1 less, or x-1
So x + (x-1) ≤ 19
x + x - 1 ≤ 19
2x - 1 ≤ 19
2x ≤ 20
x ≤ 10
The larger integer must be less than or equal 10.
It wasn't mentioned in the problem, but if the integers
must be positive then the larger would also have to be
greater than or equal to 2, so that the smaller would be
1 or more.
Edwin