SOLUTION: Why would 3>=-6 become o>=-9 ? The problem is .... 3(1-x) >= -3(x+2) why wouldn't it be 3 >= -6 (all real numbers)

Algebra ->  Inequalities -> SOLUTION: Why would 3>=-6 become o>=-9 ? The problem is .... 3(1-x) >= -3(x+2) why wouldn't it be 3 >= -6 (all real numbers)       Log On


   

Question 1081633: Why would 3>=-6 become o>=-9 ?
The problem is .... 3(1-x) >= -3(x+2) why wouldn't it be 3 >= -6 (all real numbers)
Found 3 solutions by stanbon, MathLover1, addingup:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The problem is .... 3(1-x) >= -3(x+2) why wouldn't it be 3 >= -6 (all real numbers)
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3 - 3x >= -3x -6
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3 >= -6
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Ans:: All Real Numbers
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Cheers,
Stan H.
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Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

3%281-x%29+%3E=+-3%28x%2B2%29........first both sides multiply by 3
3-3x+%3E=+-3x-6..........now you can add -3 to the both sides{ to, actually, move 3 from left to right side)
3-3-3x+%3E=+-3x-6-3
cross%283%29-cross%283%29-3x+%3E=+-3x-6-3........3-3=0
0-3x+%3E=+-3x-9..now you can add 3x to the both sides
0-3x%2B3x+%3E=+-3x%2B3x-9
0-cross%283x%29%2Bcross%283x%29+%3E=+-cross%283x%29%2Bcross%283x%29-9
0-0+%3E=+0-9
0+%3E=+-9



Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
3(1 - x) >= -3(x + 2) distribute the 3 and -3 (Distributive Property of Multiplication)
3 - 3x >= -3x + -6
subtract 3 on both sides:
-3x >= -3x + -9
Now add 3x on both sides:
-3x + 3x >= -3x + 3x - 9
0x, or just 0, >= -9
This is correct because 0 IS greater than -9 (I wrote bigger in the picture I made you, it should say greater)