SOLUTION: Can you help me with this problem : A man bought x boxes of doughnuts for $3.49 each. He paid with a $50 bill and received the correct amount of change. If he received more than $1

Algebra ->  Inequalities -> SOLUTION: Can you help me with this problem : A man bought x boxes of doughnuts for $3.49 each. He paid with a $50 bill and received the correct amount of change. If he received more than $1      Log On


   



Question 1081489: Can you help me with this problem : A man bought x boxes of doughnuts for $3.49 each. He paid with a $50 bill and received the correct amount of change. If he received more than $10 but less than $20, which inequality represents the number of boxes of doughnuts he could have bought?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+3.49x+ is the amount that he paid
His change was +50+-+3.49x+
--------------------------------
(1)
+50+-+3.49x+%3E+10+
+50+%3E+10+%2B+3.49x+
+40+%3E+3.49x+
writing this in the other direction:
+3.49x+%3C+40+
+x+%3C+11.46+
and
+50+-+3.49x+%3C+20+
+50+%3C+3.49x+%2B+20+
+30+%3C+3.49x+
write this the other way:
+3.49x+%3E+30+
+x+%3E+8.59+
--------------------
Since he couldn't have a fraction of a box,
I would change these to:
+x+%3C+12+ ( note that +11+ is allowed }
+x+%3E+9+ ( note that +8+ is NOT allowed )
-------------------------------------------
I can combine these as:
+9+%3C+x+%3C+12+
You can get another opinion also ( if needed )