SOLUTION: Twice the sum of x+8 is less than or equal to 16

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Question 1057708: Twice the sum of x+8 is less than or equal to 16
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

2%2A%28x%2B8%29+%3C=+16


2%2Ax%2B2%2A8+%3C=+16 Distribute


2x%2B16+%3C=+16 Multiply


2x%2B16-16+%3C=+16-16 Subtract 16 from both sides


2x+%3C=+0 Combine like terms


2x%2F2+%3C=+0%2F2 Divide both sides by 2 to isolate x


x+%3C=+0 Simplify


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So the final answer is x+%3C=+0 which is read as "x is less than or equal to 0"