SOLUTION: how would you find the least common multipul and make all fractions equal to the problem 1/-x, 2/y, 1/z and s/s, s/rs, s/r?

Algebra ->  Inequalities -> SOLUTION: how would you find the least common multipul and make all fractions equal to the problem 1/-x, 2/y, 1/z and s/s, s/rs, s/r?      Log On


   



Question 105342: how would you find the least common multipul and make all fractions equal to the problem 1/-x, 2/y, 1/z and s/s, s/rs, s/r?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First we need to find the GCF of each denominator 1/-x, 2/y, 1/z, s/s, s/rs, and s/r. Since none of these denominators have anything in common, the GCF is 1



Now to find the LCM, simply multiply every denominator to get

-x%2Ay%2Az%2As%2Ars%2Ar=-xyzr%5E2s%5E2

Now divide -xyzr%5E2s%5E2 by the GCF 1 to get -xyzr%5E2s%5E2. This may seem trivial, but I'm just giving you an idea on how to find the LCM.


So the LCM is

-xyzr%5E2s%5E2