SOLUTION: I don't know how to solve this problem - please help Solve the system by addition method Eq 1 states: .18x + .27y = .09 Eq 2 states: .06x

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Question 102824This question is from textbook
: I don't know how to solve this problem - please help
Solve the system by addition method
Eq 1 states: .18x + .27y = .09
Eq 2 states: .06x - .54y = -.04
I'm really stuck here, and need some help This question is from textbook

Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website!
YOU HAVE 2 CHOICES HERE:
YOU CAN MULTIPLY THE FIRST EQUATION BY 2 (ELIMINATE THE Y TERM OR MULTIPLY THE SECOND EQUATION BY -3 (ELIMINATES THE X TERM)& THEN ADD THEM.
.36X+.54Y=.18
.06X-.54Y=-.04 NOW ADD:
-----------------------------------
.42X=.14
X=.14/.42
X=1/3 ANSWER.
NOW REPLACE X BY 1/3 & SOLVE FOR Y.
.06*1/3-.54Y=-.04
.02-.54Y=-.04
-.54Y=-.04-.02
-.54Y=-.06
Y=-.06/-.54
Y=1/9 ANSWER.
PROOF
.18*1/3+.27*1/9=.09
.06+.03=.09
.09=.09

SOLUTION: I don't know how to solve this problem - please help Solve the system by addition method Eq 1 states: .18x + .27y = .09 Eq 2 states: .06x - .54y = -.04 I'm really stuck