SOLUTION: what is the sum of all integer values of x such that 31/90 < x/100 < 41/110 is true?
The answer is 108. How?
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-> SOLUTION: what is the sum of all integer values of x such that 31/90 < x/100 < 41/110 is true?
The answer is 108. How?
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Question 1008112: what is the sum of all integer values of x such that 31/90 < x/100 < 41/110 is true?
The answer is 108. How? Found 3 solutions by fractalier, MathLover1, MathTherapy:Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! 31/90 = .3444444
41/110 = .372727272
How many hundredths are in between them?
Well, 35/100, 36/100, and 37/100...
35 + 36 + 37 = 108
You can put this solution on YOUR website!
what is the sum of all integer values of x such that 31/90 < x/100 < 41/110 is true?
The answer is 108. How?
------------ Multiplying by LCD,
It then becomes: --------- Dividing by 99
Integers are therefore: