SOLUTION: Can you please help solve this problem: Julia is 20 years younger than allison. In two years Allison will be twice as old as Julia. How old are they now?

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Question 1006744: Can you please help solve this problem:
Julia is 20 years younger than allison. In two years Allison will be twice as old as Julia. How old are they now?
Found 3 solutions by Alan3354, josgarithmetic, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The difference will always be 20 years.
2x --> 20 & 40

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y for Julia and x for Allison. From that just transcribe what is written for the description and solve system of equations.

system%28y=x-20%2Cx%2B2=2%28y%2B2%29%29

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +j+ = Julia's age now
Let +a+ = Allison's age now
+j+%2B+2+ = Julia's age in 2 years
+a+%2B+2+ = Allison's age in 2 years
------------------------------
(1) +j+=+a+-+20+
(2) +a+%2B+2+=+2%2A%28+j+%2B+2+%29+
-----------------------
(1) +a+-+j+=+20+
and
(2) +a+%2B+2+=+2j+%2B+4+
(2) +a+-+2j+=+2+
--------------------
Subtract (2) from (1)
(1) +a+-+j+=+20+
(2) +-a+%2B+2j+=+-2+
--------------------
+j+=+18+
and
(1) +a+-+j+=+20+
(1) +a+-+18+=+20+
(1) +a+=+38+
---------------
Allison is 38
Julia is 18
--------------
check:
(2) +a+%2B+2+=+2%2A%28+j+%2B+2+%29+
(2) 38+%2B+2+=+2%2A%28+18+%2B+2+%29+
(2) +40+=+2%2A20+
(2) +40+=+40+
OK