SOLUTION: I need help solving this the sum of twice a number and three is greater than forty nine

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Question 883840: I need help solving this the sum of twice a number and three is greater than forty nine

Found 2 solutions by montecristo73, josmiceli:
Answer by montecristo73(8) (Show Source):
You can put this solution on YOUR website!
There is a number here which we don't know, so we will call it x.
Twice that number is the same as saying 2x.
So... 2x + 3 > 49
Now we solve as if it was an equation. We add -3 to both sides and we get...
2x > 46
We divide both sides by 2 to isolate x...
x > 23
There you go. Any number greater than 23 is a correct answer to your problem. Let's verify by substituting x for 24.
2(24) + 3 > 49
48 + 3 > 49
51 > 49
Yep! It checks!

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let the unknown number =
given:

Subtract from both sides

Divide both sides by

-----------------------
You can check this by first letting

not true
---------------------
Next let

true
So, the answer looks correct