SOLUTION: If the quotient of a number and 6 is added to twice the number, the result is 8 less than the number. Find the number. I set it up like x/6 +2x = x-8, but when I check it it does

Algebra ->  Human-and-algebraic-language -> SOLUTION: If the quotient of a number and 6 is added to twice the number, the result is 8 less than the number. Find the number. I set it up like x/6 +2x = x-8, but when I check it it does      Log On


   



Question 84879: If the quotient of a number and 6 is added to twice the number, the result is 8 less than the number. Find the number.
I set it up like x/6 +2x = x-8, but when I check it it doesn't equal.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Your initial set-up is quite ok!
x%2F6+%2B+2x+=+x-8 Simplify by multiplying through by 6.
x+%2B+12x+=+6x-48 Combine like-terms.
13x+=+6x-48 Subtract 6x from both sides.
7x+=+-48 Finally, divide both sides by 7.
x+=+-48%2F7
Check: Substitute x+=+-48%2F7
%28-48%2F7%29%2F6+%2B+2%28-48%2F7%29+=+%28-48%2F7%29-8 Simplify.
-8%2F7+-+96%2F7+=+-48%2F7+-+56%2F7
-104%2F7+=+-104%2F7 It checks!