SOLUTION: find two consecutive even numbers so that 5 times the first exceeds 3 times the second by 54.

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Question 840161: find two consecutive even numbers so that 5 times the first exceeds 3 times the second by 54.
Found 2 solutions by thejackal, ewatrrr:
Answer by thejackal(72) About Me  (Show Source):
You can put this solution on YOUR website!
important to remember that if they are consecutive even then the second number will be 2 + the first number.
So let our two numbers be x and y. y is therefore really x + 2;
Now we want to choose and x and consequently a y such that x times 5 is exactly 54 larger than 3 times y;
this can be first expressed like so: 5x > 3y by 54; write this properly it becomes 5x > 3(x + 2) + 54; turn this inequality into an equation by subtracting 54 from both sides to get;
5x - 54 = 3x + 6
solve for x
5x - 3x = 6 + 54 which when simplified becomes 2x = 60 thus x = 30
now to find y we go back to our original equation for it x + 2 = 30 + 2 = 32

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

find two consecutive even numbers highlight_green%28x%29 and highlight_green%28x%2B2%29

so that 5 times the first exceeds 3 times the second by 54.

Question states***

  5x = 3(x+2) -54

  5x = 3x + 6 -54

  2x = -48

   x = -24

two consecutive even numbers are: -24, -22

CHECKING our answer***

-120 = -66-54