SOLUTION: Solution A is 40% alcohol and 60% water . Solution B is 42% alcohol and 58% water. How much of each solution must be mixed to make 120 quarts of a solution that is 30% alcohol?

Algebra ->  Human-and-algebraic-language -> SOLUTION: Solution A is 40% alcohol and 60% water . Solution B is 42% alcohol and 58% water. How much of each solution must be mixed to make 120 quarts of a solution that is 30% alcohol?       Log On


   

Question 815417: Solution A is 40% alcohol and 60% water . Solution B is 42% alcohol and 58% water. How much of each solution must be mixed to make 120 quarts of a solution that is 30% alcohol?
Thanks so much in advance:)
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The problem is impossible to solve
as stated. With a 40% mixture and a
42% mixture, there is no way you can
end up with a smaller percentage of
alcohol than 40% or a larger percentage
of alcohol than 42%
Are you sure the data is correct?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
This was posted previously and I said it's not possible.
No matter how many times you post it, there's no solution (no pun).