Question 75604This question is from textbook Fundamentals of Mathmatics
: Addie has $2.15 in her change purse, consisting of nickels, dimes, and quarters. If she has twice as many nickels as quarters and one less dime than quarters, how many of each coin does she have?
This question is from textbook Fundamentals of Mathmatics
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Addie has $2.15 in her change purse, consisting of nickels, dimes, and quarters.
:
The equation:
.05n + .10d + .25q = 2.15
;
Write an equation for each phrase:
"If she has twice as many nickels as quarters"
n = 2q
:
" and one less dime than quarters,"
d = (q - 1)
:
We can put everything in terms of q and solve for that:
Substitute 2q for n, (q-1) for d) in the original equation:
:
.05(2q) + .10(q-1) + .25q = 2.15
.1q + .1q - .1 + .25q = 2.15
.45q = 2.15 + .1
.45q = 2.25
q = 2.25/.45
q = 5 quarters
:
n = 2(5) = 10 nickels
:
d = 5 - 1 = 4 dimes
:
:
Check: .05(10) + .1(4) + .25(5) =
.5 + .4 + 1.25 = 2.15, check our solutions
:
Make sense to you?
|
|
|
