SOLUTION: find the pair of consecutive integers such that the sum of twice the smaller even integer and 10 times the larger even integer is 500

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Question 665431: find the pair of consecutive integers such that the sum of twice the smaller even integer and 10 times the larger even integer is 500
Found 2 solutions by ReadingBoosters, mananth:
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Given
x x+2
2x+10(x+2)=500
...
Solve for x
..
2x + 10x + 20 = 500
12x = 500 - 20
12x = 480
x = 40
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Integers are 40 and 42
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Check

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Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the even integers be x & x+2
2x+10(x+2)=500
2x+10x+20=500
30x=500-20
30x=480
/30
x= 16
The consecutive even integers are 16 & 18
m.ananth@hotmail.ca