SOLUTION: The gym is 21 years newer than the auditorium. the gym is also one fourth as old as the auditorium. How old is each building? (26,27,28) possible ages for auditorium Write an

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Question 52910This question is from textbook algebra structure and method
: The gym is 21 years newer than the auditorium. the gym is also one fourth as old as the auditorium. How old is each building?
(26,27,28) possible ages for auditorium
Write an equation as well as solve.
This question is from textbook algebra structure and method

Found 2 solutions by tutorcecilia, ankor@dixie-net.com:
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
Age of the Auditorium = unknown = n
Age of the Gym = n-21 [The gym is 21 years newer than the auditorium]
Age of the Gym = (1/4)n [the gym is also one fourth as old as the auditorium]
Gym = Gym
So, n-21=(1/4)n
n-n-21=(1/4)n-n [Isolate all of the terms to one side of the equation]
21=(3/4)n
0=(3/4)n-21 [Equation of the problem]
.
(3/4)n -21=0 [solve for "n"]
(3/4)n-21+21=0+21
(3/4)n=21
(4/3)(3/4)n=(21)(4/3)
n=28= the age of the auditorium
.
Check by plugging (n=28) back into the original equations
Age of the Gym = n-21 = 28-21=7
Age of the Gym = (1/4)n = (1/4)(28/1)=7
[checks out]

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Human-and-algebraic-language/52910 (2006-09-19 18:07:18): The gym is 21 years newer than the auditorium. the gym is also one fourth as old as the auditorium. How old is each building?
:
(26,27,28) possible ages for auditorium
:
Write an equation as well as solve.
:
:
a = age of the auditorium
:
"The gym is 21 years newer than the auditorium."
[a-21] = age of the gym
:
"the gym is one fourth as old as the auditorium."
[a-21] = .25a
a -.25a = + 21
.75a = 21
a = 21/.75
a = 28 years old
:
:
Check: Gym = 28 - 21 = 7 years, which is 1/4 of 28