SOLUTION: The ages of a mother and daughter are the same but the digits are reversed.Twelve years ago, the mother was twice as old as the daughter. How old are they now?
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Question 448813: The ages of a mother and daughter are the same but the digits are reversed.Twelve years ago, the mother was twice as old as the daughter. How old are they now? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The ages of a mother and daughter are the same but the digits are reversed.
Let 10x+y = mom's age
then
10y+x = daughter's age
:
Twelve years ago, the mother was twice as old as the daughter.
10x+y - 12 = 2(10y+x-12)
10x + y - 12 = 20y + 2x - 24
10x - 2x = 20y - y - 24 + 12
8x = 19y - 12
Divide by 8
x = y -
x = y -
only one value for y gives an integer value for x, that is
y = 4
then
x = (4) -
x = -
x = 9.5 - 1.5
x = 8
:
Mom's age: 84, Daughter 48
:
:
See if that's true in the statement
"Twelve years ago, the mother was twice as old as the daughter."
84 - 12 = 2(48 - 12)
72 = 2(36)
