SOLUTION: Hello I was wondering can you help me solve this problem. Not for sure what my next step would be. Problem :A basketball court is a rectangle with a perimeter of 80 meter

Click here to see ALL problems on Human-and-algebraic-language

Question 414453: Hello I was wondering can you help me solve this problem. Not for sure what my next step would be.

Problem :A basketball court is a rectangle with a perimeter of 80 meters . The length is 13 meters more than the width. Find the width and length of basketball court.

My attempt: Let x be width
Let Y be length
X+13=width
x+13= 80 meters
-13=-13
x= 67 meters.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Problem :A basketball court is a rectangle with a perimeter of 80 meters . The length is 13 meters more than the width. Find the width and length of basketball court.
---
Let width be "x":
Then lenght = "x+13".
---
Equation:
P = 2(width + length)
80 = 2(x + x+13)
40 = 2x+13
2x= 27
x = 13.5 meters (width)
x+13 = 26.5 meters
---
Cheers,
Stan H.

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
The perimeter of any rectangle is
given:
Width =
Length =

----------

and

The width is 13.5 m and the length is 26.5 m
check answer:

OK