Question 400979: Pablo, Faustina, and Mark swim at a public pool each day for exercise. One day Pablo swam 5 more than 3 times as many laps as Mark, and Faustina swam four times as many laps as Mark. If the men swam 29 laps altogether, how many laps did each one swim?
What I have done:
29=5+3m
24=3m
24/3=3m/3
7=m
Pablo swam 7 laps
29=4m
29/4=4m/4
7 1/4=m
Faustina swam 7 and 1/4 laps
29-7=22-7 1/4=14 3/4
Mark swam 14 and 3/4 laps
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let m= Number of laps for Mark
3m+5 = Number of laps for Pablo
4m= Number of laps for Faustina
The TOTAL number of laps (that means add them up!) = 29
m+3m+5 + 4m=29
8m+5 = 29
8m+5-5 = 29-5
8m= 24
m=3 Mark
3m+5 = 3*3 + 5 = 14 Pablo
4m= 4*3= 12 = Faustina
Check: 3+14+12 = 29
It checks!!
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