SOLUTION: A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far
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-> SOLUTION: A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far
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Question 390193: A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far is the automobile for him.
(Can you please explain in details how the answer is found.)
thank you ! Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far is the automobile for him.
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draw a sketch
a rectangle ABCD
..
A man
B vertical point below the man
C= car position
D = vertical position above car in line with A
..
We have to find length AC.
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angle DAC = angle of depression = 26deg.22'
this is = angle ACB . alternate angles
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sine angle ACB = vertical / hypotenuse (AC)
sine 26 degrees 22 minutes = 550/AC
AC = 550/sine 26 degrees 22 minutes
AC = 1238 feet
.../
m.ananth@hotmail.ca
