SOLUTION: the perimeter of a rectangular lot is 190 ft. the width of the lot is 15ft more than the length. what are the dimensions of the lot. P=2L+2W W=L+15 190=2L+2(L+15) 190=2L+2L+

Algebra ->  Human-and-algebraic-language -> SOLUTION: the perimeter of a rectangular lot is 190 ft. the width of the lot is 15ft more than the length. what are the dimensions of the lot. P=2L+2W W=L+15 190=2L+2(L+15) 190=2L+2L+      Log On


   

Question 337467: the perimeter of a rectangular lot is 190 ft. the width of the lot is 15ft more than the length. what are the dimensions of the lot.
P=2L+2W
W=L+15
190=2L+2(L+15)
190=2L+2L+30
190-30=4L
160/4=L
40=L
W=40+15=55
DIMENSIONS IS 55 FEET BY 40 FEET.
Answer by chiexpert(48) About Me  (Show Source):
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P=2L+2W
W=L+15
190=2L+2(L+15)
190=2L+2L+30
190-30=4L
160/4=L
40=L
W=40+15=55
DIMENSIONS IS 55 FEET BY 40 FEET.