SOLUTION: The velocity ds/dt (in meters/second) of a projectile is given by ds/dt=-9.8t+16 Find the displacement s of the object after 4 seconds if the initial displacement is 48 m

Algebra ->  Human-and-algebraic-language -> SOLUTION: The velocity ds/dt (in meters/second) of a projectile is given by ds/dt=-9.8t+16 Find the displacement s of the object after 4 seconds if the initial displacement is 48 m      Log On


   



Question 328500: The velocity ds/dt (in meters/second) of a projectile is given by
ds/dt=-9.8t+16
Find the displacement s of the object after 4 seconds if the initial displacement is 48 m.

Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The velocity ds/dt (in meters/second) of a projectile is given by
ds/dt=-9.8t+16
Find the displacement s of the object after 4 seconds if the initial displacement is 48 m.
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s = the integral of ds/dt
s = -4.9t^2 + 16t + C
C = 48 m, the initial displacement
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s(t) = -4.9t^2 + 16t + 48
s(4) = -4.9*16 + 64 + 48
s(4) = 33.6 meters

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Integrate,
ds%2Fdt=-9.8t%2B16
s=-4.9t%5E2%2B16t%2BC
s%280%29=0%2B0%2BC=48
C=48
.
.
.
s%28t%29=-4.9t%5E2%2B16t%2B48
s%284%29=-4.9%2816%29%2B64%2B48
s%284%29=33.6m