SOLUTION: Part of a $12,000 investment earned interest at a rate of 7%, and the rest earned interest at a rate of 9%. The combined interest earned at the end of 1 year was $890. How much was

Algebra ->  Human-and-algebraic-language -> SOLUTION: Part of a $12,000 investment earned interest at a rate of 7%, and the rest earned interest at a rate of 9%. The combined interest earned at the end of 1 year was $890. How much was      Log On


   



Question 257358: Part of a $12,000 investment earned interest at a rate of 7%, and the rest earned interest at a rate of 9%. The combined interest earned at the end of 1 year was $890. How much was invested at each rate?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
This is a I=PRT problem. IN this case we have 2 rates,so we get
(i) I+=+prt+%2B+prt
From above, (i) becomes
(ii) 890+=+x%28.07%29%281%29+%2B+%2812000-x%29%28.09%29%281%29
which is
890+=+.07x+%2B+1080+-.09x
890+=+-.02x+%2B+1080
.02x+=+190
x = 9500
12000-x = 2500
So it appears we have
9500 @ 7%
2500 @ 9%