SOLUTION: eight times a number plus five times another number is -13.the sum of the two numbers is 1.what are the numbers. please help me solve this its about elimination using multipli

Algebra ->  Human-and-algebraic-language -> SOLUTION: eight times a number plus five times another number is -13.the sum of the two numbers is 1.what are the numbers. please help me solve this its about elimination using multipli      Log On


   

Question 257029: eight times a number plus five times another number is -13.the sum of the two numbers is 1.what are the numbers.

please help me solve this its about elimination using multiplication.i think
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = "a number
Let y = "another number"
:
Write an equation for each statement:
:
"eight times a number plus five times another number is -13."
8x + 5y = -13
:
"the sum of the two numbers is 1."
x + y = 1
:
what are the numbers.
We can us elimination here if you want.
:
Multiply the above equation by 5 and subtract from the 1st equation
8x + 5y = -13
5x + 5y = 5
----------------Subtraction eliminates y find x
3x = -18
x = %28-18%29%2F3
x = -6
:
Find x using x + y = 1
-6 + y = 1
y = 1 + 6
y = 7
:
Solution x = -6, y = 7
:
:
Check solution in the 1st statement
eight times a number plus five times another number is -13
8(-6) + 5(7) =
-48 + 35 = -13; confirms our solutions