SOLUTION: The perimeter of a rectangle is 44 meters. The length is 2 meters more than the three times the width. Find the length.
Algebra ->
Human-and-algebraic-language
-> SOLUTION: The perimeter of a rectangle is 44 meters. The length is 2 meters more than the three times the width. Find the length.
Log On
Question 222997: The perimeter of a rectangle is 44 meters. The length is 2 meters more than the three times the width. Find the length. Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 44 meters. The length is 2 meters more than the three times the width. Find the length.
Step 1. The perimeter P means adding up all four sides of a rectangle.
Step 2. Let w be the width
Step 3. Let 3w be three times the width
Step 4. Let 3w+2 be the length since it is 2 meters more than three times the width
Step 5. Then P=w+w+3w+2+3w+2=8w+4=44 since the perimeter P is 44 meters.
Step 6. Solving the equation in Step 4 leads to the following steps
Subtract four from both sides
Divide by 8 to both sides of the equation
and 3w+2=15+2=17 and P=2(5+17)=44 which is a true statement.
Step 7. The length is 17 meters.
I hope the above steps and explanation were helpful.
For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry.
Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.
