SOLUTION: A girl walked 1/3 of the way at 3 mph and got a car ride the rest of the way at 30 mph. What was her average speed?

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Question 203796: A girl walked 1/3 of the way at 3 mph and got a car ride the rest of the way at 30 mph. What was her average speed?
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A girl walked 1/3 of the way at 3 mph and got a car ride the rest of the way at 30 mph. What was her average speed?
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average speed = total distance/total time
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Your Problem:
Let the total trip distance be x miles:
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Walking time = distance/rate = [(1/3)x]/[3 mph] = x hrs
Riding time = distance/rate = [(2/3)x]/[30 mph] = 20x hrs.
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Therefore average speed = x miles/(21x hrs) = (1/21) mph
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Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

D = RT

Let the distance the girl traveled be d. Since her rate of speed is 3 mph, then for the first 1%2F3 of the journey, her time to cover “d” distance is:

%281%2F3%2Ad%29+%2F3, or %28d%2F3%29%2A%281%2F3%29, or d%2F9
Since her rate of speed for the rest of the journey, 2%2F3 is 30 mph, then for the rest of the journey, her time to cover that distance is:

%282%2F3%2Ad%29+%2F30, or %282d%2F3%29%2A%281%2F30%29, or, d%2F45%29. The total time she took for the entire journey is therefore %28d%2F9%29%2B%28d%2F45%29%29, or 6d%2F45 = 2d%2F15

Since her total time to cover the entire distance is 2d%2F15, and since her total journey = “d,” then her average speed = d%2F%282d%2F15%29, or, 15%2F2 = highlight_green%287.5%29 mph.