SOLUTION: A parking lot has a perimeter of 600ft. The width is 30ft less than the lenght. Find the dimensions of the parking lot. Thank you.

Algebra ->  Human-and-algebraic-language -> SOLUTION: A parking lot has a perimeter of 600ft. The width is 30ft less than the lenght. Find the dimensions of the parking lot. Thank you.      Log On


   

Question 162644: A parking lot has a perimeter of 600ft. The width is 30ft less than the lenght. Find the dimensions of the parking lot.
Thank you.
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
A parking lot has a perimeter of 600ft. The width is 30ft less than the lenght. Find the dimensions of the parking lot.

P=L%2AW, EQN 1
But, W=L-30ft
So,
P=L%28L-30ft%29,
600ft=L%5E2-30L
L%5E2-30L-600=0
*Note: system%28a=1%2Cb=-30%2Cc=-600%2Cx=L%29
By Pyth theorm: x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
ANSWER: x=L=43.723ft
And, W=43.723-30=13.723ft
In doubt? go back EQN 1,
600ft=43.723%2A13.723
600ft=600.01ft, close enough! Because we round off x (Length)
Thank you,
Jojo