SOLUTION: Thirty students bought pennants for the football game. Plain pennants cost $4 each and fancy ones cost $8 each. If the total bill was $168, how many students bought the fancy penna
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-> SOLUTION: Thirty students bought pennants for the football game. Plain pennants cost $4 each and fancy ones cost $8 each. If the total bill was $168, how many students bought the fancy penna
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Question 162161: Thirty students bought pennants for the football game. Plain pennants cost $4 each and fancy ones cost $8 each. If the total bill was $168, how many students bought the fancy pennants. Found 2 solutions by tutor_paul, jojo14344:Answer by tutor_paul(519) (Show Source):
You can put this solution on YOUR website! Let x=number of students who bought fancy pennants.
Let y=number of students who bought plain pennants.
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From the information given, you can write the following equation:
Equation#1:
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From the information given, you can also write the following equation:
Equation#2:
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Now, this is a problem of 2 equations and 2 unknowns. Any time you can develop as many equations as you have unknowns, you can solve the problem!
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Use the substitution method. First, solve Equation #1 for y:
Substitute this expression for y into Equation #2:
Solve for x and you are done:
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Good Luck,
tutor_paul@yahoo.com
You can put this solution on YOUR website!
Total Pennants sold: ----------> EQN 1
In EQN 1, we get, --------------------------> EQN 2
Also, -----------------------> EQN 3
Subst. EQN 2 in EQN 3:
Via EQN 2:
In doubt? Go back EQN 3,
Thank you,
Jojo
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