SOLUTION: four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple.
Algebra ->
Human-and-algebraic-language
-> SOLUTION: four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple.
Log On
Question 132676This question is from textbook Algebra 1
: four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple. This question is from textbook Algebra 1
You can put this solution on YOUR website! four oranges and five apples cost $3.56. three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple.
-----------------
EQUATIONS:
4R + 5A = 3.56
3R + 4A = 2.76
------------------
Multiply 1st by 3 and 2nd by 4 to get:
12R + 15A = 3*3.56
12R + 16A = 4*2.76
--------------------
Substract 1st from 2nd to get:
A = 0.36 (price of an apple)
Substitute to solve for R:
4R + 5*0.36 = 3.56
4R = 1.76
R = 0.44 (prince of an orange)
===================================
Cheers,
Stan H.
(