SOLUTION: The sum of two numbers is twenty-six. Four less than five times the smaller is equal to the larger.

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Question 1205899: The sum of two numbers is twenty-six. Four less than five times the smaller is equal to the larger.
Found 3 solutions by Theo, josgarithmetic, ikleyn:
Answer by Theo(13342) About Me  (Show Source):
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let A be the largest number and let B be the smallest number.
you have two equations that need to be solved simultaneously.
they are:
A + B = 26
A = 5B - 4
in the first equation, replace A with 5B - 4 from the second equation to get 5B - 4 + B = 26
combine like terms to get 6B - 4 = 26
add 4 to both sides of the equation to get 6B = 30
solve for B to get B = 30/6 = 5.
A + B = 26 becomes A + 5 = 26
solve for A to get A = 21.
your solution is that the larger number is 21 and the smaller number is 5.

Answer by josgarithmetic(39617) About Me  (Show Source):
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Sum of the two, 26.
Numbers n and 26-n.


Second sentence of description:
-4%2B5%2826-n%29=n
-
-4%2B130-5n=n
126=6n
n=21

The two numbers are 21 and 5.

Answer by ikleyn(52779) About Me  (Show Source):
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.

The answer  " 21  and  25 "  in the post by  @josgarithmetic is  INCORRECT.

The correct answer is  " the numbers are  5  and  21 "  from the post by  @Theo.

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@josgarithmetic just fixed his error after seeing my post.