SOLUTION: solve the exponential equation by using the property that bx = by implies x = y, for b> 0 and b ≠ 1
27^1/3x=(1/9)^2x-1
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-> SOLUTION: solve the exponential equation by using the property that bx = by implies x = y, for b> 0 and b ≠ 1
27^1/3x=(1/9)^2x-1
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Question 1088326: solve the exponential equation by using the property that bx = by implies x = y, for b> 0 and b ≠ 1
27^1/3x=(1/9)^2x-1 Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
solve the exponential equation by using the property that bx = by implies x = y, for b> 0 and b ≠ 1
27^1/3x=(1/9)^2x-1
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1. Before solving this problem, let me say you that the formulation in the post is not correct.
The correct formulation, PROBABLY, is THIS:
solve the exponential equation by using the property that b^x = b^y implies x = y, for b> 0 and b ≠ 1
27^1/3x=(1/9)^2x-1
(By saying PROBABLY, I am actually 120% sure).
2. Now the solution:
27^((1/3)*x) = (1/9)^(2x-1) ====>
3*(3*(1/3)*x) = (1/3)^(2*(2x-1)) ====>
= ====>
= ====>
x = -4x + 2 ====> 5x = 2 ====> x = = 0.4.
