SOLUTION: The sum of three consecutive natural numbers is 1941, find the numbers.

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Question 1047183: The sum of three consecutive natural numbers is 1941, find the numbers.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive numbers be:
+n+, +n%2B1+, and +n%2B2+
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given:
+n+%2B+n+%2B+1+%2B+n+%2B+2+=+1941+
+3n+%2B+3+=++1941+
+3n+=+1938+
+n+=+646+
and
+n%2B1+=+647+
+n%2B2+=+648+
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The 3 consecutive numbers are 646, 647, and 648
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check:
+n+%2B+n+%2B+1+%2B+n+%2B+2+=+646+%2B+647+%2B+648+
+n+%2B+n+%2B+1+%2B+n+%2B+2++=+1941+
OK