SOLUTION: A moving van leaves a house traveling at an average rate of 35 mi/h.The family
leaves the house hour later following the same route in a car.They travel at
an average rate of 50
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-> SOLUTION: A moving van leaves a house traveling at an average rate of 35 mi/h.The family
leaves the house hour later following the same route in a car.They travel at
an average rate of 50
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Question 102349This question is from textbook Algebra
: A moving van leaves a house traveling at an average rate of 35 mi/h.The family
leaves the house hour later following the same route in a car.They travel at
an average rate of 50 mi/h. How long after the moving van leaves the house will
the car catch up with the van? This question is from textbook Algebra
You can put this solution on YOUR website! A moving van leaves a house traveling at an average rate of 35 mi/h.The family
leaves the house hour later following the same route in a car.They travel at
an average rate of 50 mi/h. How long after the moving van leaves the house will
the car catch up with the van?
:
Let t = travel time of the van when the car overtakes it
then
(t-1) = travel time of the car when this happens
:
They will have traveled the same distance when the car overtakes the van
Write a distance equation from the fact. Distance = speed * time
:
Car dist = van dist
50(t-1) = 35t
50t - 50 = 35t
50t - 35t = +50
15t = 50
t = 50/15
t = 3 hrs or 3 hrs, 20 min
:
Check solution by finding the distance of both, should be equal
Van: 3 * 35 = 166 miles
Car: 2 * 50 = 166 miles
