Tutors Answer Your Questions about Graphs (FREE)
Question 115526: Please help. I have asked several time with not response I think because the topic may be incorrect. I am just not sure which topic to oick but I really need help.
Solve the following system of linear inequalities by graphing.
x+2y≤3
2x-3y≤6
Thanks
JMS
Click here to see answer by jim_thompson5910(35256)  |
Question 115837: Hello I need some help.
As the number of farms has decreased in llinios, the average size of the remianing farms has grown larger,as shown below
Year Average Acreage per farm
1900 127
1910 119
1920 135
1930 137
1940 155
1950 196
1960 283
1970 353
1980 406
1990 440
2000 420
let x represent the number of years since 1900. Use a graphing calculator to fit a function to the data. Select the model which gives best fit. Write the equation , the coeffienct of determination, and estimate to nearest arce the average acreage in 2011. Use regression feature in calculator. This problem is really hard can anyone help me thanks
Click here to see answer by stanbon(75887) |
Question 115842: which of these equationss represent a vertical line?
i 2x - 3y = 6
ii 2x + 3y = 6
iii 2x = 6
iv 3y = 6
I think the answer is "iv" but that's cause i worked it out in my head. y=2. But i am not too sure how to go about proving the first 2 wrong???
Thanks
Click here to see answer by checkley71(8403) |
Question 116017: Can someone help me with this graphing?
Describe the transformations on the following graph of f(x)=log(x). State the replacement of the verticle asymptote and x-intercept after the transformation. For example, "left 1" or stretched vertically by a factor of 2" or descriptions.On my graph i see a line from -2 on the y axis and 10 on the x-axis
a)g(x)=log(x+2)
Description of transformation:
Vertical asymptote:
x-intercept in (x,y) form:
b) g(x)= -log(x)
Description of transformation:
Vertical asymptote:
x-intercept in (x,y)form:
Need help asap
Thankyou
Click here to see answer by jim_thompson5910(35256) |
Question 116010: This is not exactly what my problem is but it's the closest thing I could understand. The problem says "Coffee worth $3.75 a pound was mixed with coffee worth $4.35 a pound to produce a blend worth $4.11 a pound. How much of each kind of coffee was used to produce 40 pounds of blended coffee?" My problem is finding the equations to solve by elimination because, this seems to need 3 variables in order to be made into the first equation. Hope I explained it well enough for you to help.
Click here to see answer by scott8148(6628)  |
Question 116265: Solve by graphing: x^2+y^2=25 and x-2y=-5
I graphed my circle and line perfectly
but when it came to using either addition or substitution methods
to find the solution set (where the line crosses the circle at two points)
I had problems:(
I can see by looking at my graph that one solution is (-5,0) and the other
is approximately (3.5, 4.5) but I have to use one of the above methods
to show how I came up with my solutions and show my work.
This is what I've done so far:
Using substitution method
x^2+y^2=25 and x-2y=-5 (changed to x=2y-5) and substituted in to 1st equation
(2y-5)^2+y^2=25
4y^2-20y+25+y^2=25
(combine like terms)
5y^2-20y+25=25
(subtract 25 from each side)
5y^2-20y=0
This is where I loose it, because in class all of our problems worked out nice and neat
and all I had to do was factor my quadratic equation to come up with one solution and
then plug that into one of my original problems to get my second.
No one in study group tonight quite got this one either and this is due this Thursday!
Click here to see answer by stanbon(75887) |
Question 116265: Solve by graphing: x^2+y^2=25 and x-2y=-5
I graphed my circle and line perfectly
but when it came to using either addition or substitution methods
to find the solution set (where the line crosses the circle at two points)
I had problems:(
I can see by looking at my graph that one solution is (-5,0) and the other
is approximately (3.5, 4.5) but I have to use one of the above methods
to show how I came up with my solutions and show my work.
This is what I've done so far:
Using substitution method
x^2+y^2=25 and x-2y=-5 (changed to x=2y-5) and substituted in to 1st equation
(2y-5)^2+y^2=25
4y^2-20y+25+y^2=25
(combine like terms)
5y^2-20y+25=25
(subtract 25 from each side)
5y^2-20y=0
This is where I loose it, because in class all of our problems worked out nice and neat
and all I had to do was factor my quadratic equation to come up with one solution and
then plug that into one of my original problems to get my second.
No one in study group tonight quite got this one either and this is due this Thursday!
Click here to see answer by bucky(2189) |
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