Tutors Answer Your Questions about Graphs (FREE)
Question 87879: This is my first time on this site and the problem looks easy but I am really
having the blues. Graph y=3x=4 and y=-1/3x-4 determine whether the two lines
are parallel,perpendicular ot neither.The teacher taught it this way but I am
still having a hard time with it.
Click here to see answer by Earlsdon(6294) |
Question 88346: The sum of two numbers is 58. The second is 1 more than 2 times the first what are the two numbvers ok x+y= 58 = 2(x+1) +2y = 58= 2x + 2 +2y = 58 -2= 56 then 2x/2 = 56/2 x= 28 then 28 -56= 28 I 'm lost
Click here to see answer by rossiv53(27) |
Question 88343: word problem delimma tickets for a play cost $12 for an adult and $8 for an child If 130 tickets were sold and the total receipts were 1160 how many of each ticket weree sold. Ok if x= the adult tickets and c= the child tickets do I go x+ c = 130 and then go 12x + 8c==1160 then divide both sidec by 8 to get the child ticket
Click here to see answer by rossiv53(27) |
Question 88674: Graph the function and label as exponential growth or decay. y=3x3to the xth power. I have no idea what they're talking about. It's an algebra review part of our summer assignment for Pre AP Geometry. Help!!! Thanks! :)
Click here to see answer by cincinnatus(5) |
Question 88885: I need help with the following problems. All of these problems ar inside of the curly brackets.. example { }
Solve by any convenient method :
4x + 12y = 24
2x + 6y = 12
Solve by any convenient method :
8x + 4y =7
x = 2-2y
Solve by Elimination :
2x -3y =-1
3x + y +15
Solve by Substitution :
3x + 8y = 7
x- 4y =9
Click here to see answer by stanbon(75887) |
Question 88885: I need help with the following problems. All of these problems ar inside of the curly brackets.. example { }
Solve by any convenient method :
4x + 12y = 24
2x + 6y = 12
Solve by any convenient method :
8x + 4y =7
x = 2-2y
Solve by Elimination :
2x -3y =-1
3x + y +15
Solve by Substitution :
3x + 8y = 7
x- 4y =9
Click here to see answer by jim_thompson5910(35256) |
Question 88885: I need help with the following problems. All of these problems ar inside of the curly brackets.. example { }
Solve by any convenient method :
4x + 12y = 24
2x + 6y = 12
Solve by any convenient method :
8x + 4y =7
x = 2-2y
Solve by Elimination :
2x -3y =-1
3x + y +15
Solve by Substitution :
3x + 8y = 7
x- 4y =9
Click here to see answer by malakumar_kos@yahoo.com(315) |
Question 88889: I have solved these but wanted someone check them. Is there any way you can solve these and graph them so that I can see what they look like compared to my graph since I am unsure how to graph on this site.
It says to solve graphically. State the colution.
#1 #2
2x-y=-6 -2x+y=-4
x+y=3 y-2x=3
Click here to see answer by jim_thompson5910(35256) |
Question 88957: My teacher says what I am doing is wrong please help me with these to.
For each equation in exercises 26 and 28, identify the axis of symmetry, create a suitable
table of values, and sketch the graph (including the axis of symmetry).
26. x^2-5x+3
28. x^2+6x-2
Click here to see answer by scott8148(6628)  |
Question 89038: Word problems are hard for me. Please help with this question:
Ronald wants to sell his car through a broker who charges a commission of 10% of the selling price. Ronald still owes $11,025 ON THE CAR. Ronald must get enough to at least pay of the loan. What is the rance of the selling price.
I had 11025
Click here to see answer by scott8148(6628)  |
Question 89200: Describe the steps you would follow in graphing x+2y<=2. Include in your answer whether you use a solid or broken line and where you shade, above or below the line.
This is from a worksheet.
Click here to see answer by Nate(3500) |
Question 89510: Suppose you wanted to design a parabolic arch (a parabola opening downward) as a trellis in your garden. This would mean that the first term of the quadratic equation, the term with the variable raised to the second power, would have to be negative. An engineering friend suggests that the following quadratic function might be aesthetically pleasing.
h(x) = -5x2/64 + 4
This function gives the height of the arch (in feet) at any horizontal distance x (in feet) from the centerline of the arch. The trellis (parabola) could be supported by vertical posts at intervals across the inside of the arch. These posts could be placed at 1, 2, 3, 4, 5, 6, and 7 feet on both sides of the centerline (the axis of the parabola). Therefore, for any distance (x-value) the height of a post supporting the arch at that point could be determined from the above function.
1. When drawing the graph of this parabola, where is its axis located in the coordinate plane?
2. Where would the arch touch the ground? (i.e. How far from the axis of the parabola?)
Suppose you wanted to design a parabolic arch (a parabola opening downward) as a trellis in your garden. This would mean that the first term of the quadratic equation, the term with the variable raised to the second power, would have to be negative. An engineering friend suggests that the following quadratic function might be aesthetically pleasing.
h(x) = -5x^2/64 + 4
This function gives the height of the arch (in feet) at any horizontal distance x (in feet) from the centerline of the arch. The trellis (parabola) could be supported by vertical posts at intervals across the inside of the arch. These posts could be placed at 1, 2, 3, 4, 5, 6, and 7 feet on both sides of the centerline (the axis of the parabola). Therefore, for any distance (x-value) the height of a post supporting the arch at that point could be determined from the above function.
1. When drawing the graph of this parabola, where is its axis located in the coordinate plane? Please show the graph
2. Where would the arch touch the ground? (i.e. How far from the axis of the parabola?)
3. What is the maximum height of the arch?
4. What are the lengths of the posts at the distances of 1, 2, 3, . . . feet from the axis?
a. 1 foot from axis
b. 2 feet from axis
c. 3 feet from axis
d. 4 feet from axis
e. 5 feet from axis
f. 6 feet from axis
g. 7 feet from axis a. = b. = c. = d. = e. = f. = g. =
I have submitted this problem several times and now I think I figured out what I was doing wrong please help me.
Click here to see answer by scott8148(6628)  |
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