SOLUTION: I am trying to graph the function {{{ g(x)=log3(x-1) }}} but i'm not sure if i'm supposed to place a horizontal or a vertical asymptote/where to place it, or what points to graph i

Algebra ->  Graphs -> SOLUTION: I am trying to graph the function {{{ g(x)=log3(x-1) }}} but i'm not sure if i'm supposed to place a horizontal or a vertical asymptote/where to place it, or what points to graph i      Log On


   



Question 985840: I am trying to graph the function +g%28x%29=log3%28x-1%29+ but i'm not sure if i'm supposed to place a horizontal or a vertical asymptote/where to place it, or what points to graph it at. Step by step would be helpful.
I am also supposed to give its domain and range using interval notation.
I think the domain is (1, ∞) but i'm not 100% confident
I think the range is (-∞,∞) but again, not sure. please correct me if i'm wrong.
Help would be extremely appreciated. Thank you so much, in advance!

Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming the function is log%283%2C%28x-1%29%29

You have the correct domain and range. Nice work.

To graph this function, you can plug in various values of x to get corresponding values of y. For example, if x = 2, then y = 0 giving the ordered pair (2,0). If x = 4, then y = 1 giving another point (4,1). Do this for other values of x.
Each (x,y) pair forms a point. Plot a bunch of points and draw a smooth curve connecting the points to complete the graph.

You can use a graphing calculator like TI83 to confirm your graph. If you do not have a graphing calculator, you can use a free one like this one

Note: you'll need to type in log(x-1)/log(3)

Another note: This graph has NO horizontal asymptotes. It has exactly one vertical asymptote and it is x = 1.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!



Figure. The plot of the function y=log%283%2C%28x-1%29%29
Vertical asymptote  x=1.