SOLUTION: Find the equation of a line which slope= -1/2 and contains the point (3,2) I tried using the point slope formula y-y1=m(x-x1) but the final answer I got was y=-1/2x+0.5 which

Algebra ->  Graphs -> SOLUTION: Find the equation of a line which slope= -1/2 and contains the point (3,2) I tried using the point slope formula y-y1=m(x-x1) but the final answer I got was y=-1/2x+0.5 which       Log On


   

Question 983706: Find the equation of a line which slope= -1/2 and contains the point (3,2)
I tried using the point slope formula y-y1=m(x-x1) but the final answer I got was y=-1/2x+0.5 which doesn't seem correct to me, and I have no way of checking my answer.
An explanation of how you find the lines equation, and the formula you use would be very much appreciated.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Point-Slope is a good way to begin.
Point (p,v), and slope m:
y-v=m%28x-p%29

Your example:
y-2=%28-1%2F2%29%28x-3%29, the start.
y=%28-1%2F2%29%28x-3%29%2B2
y=-%281%2F2%29x%2B3%2F2%2B2, so you probably made a sign mistake - not sure.
y=-%281%2F2%29x%2B3%2F2%2B4%2F2
highlight%28y=-%281%2F2%29x%2B7%2F2%29 or highlight%28y=-%281%2F2%29x%2B3%261%2F2%29