SOLUTION: Complete the square on both the x and y terms to rewrite the equation 2x^2−3y^2−4x+12y−22 = 0 so that you can use the rewritten equation to relate this equation t

Algebra ->  Graphs -> SOLUTION: Complete the square on both the x and y terms to rewrite the equation 2x^2−3y^2−4x+12y−22 = 0 so that you can use the rewritten equation to relate this equation t      Log On


   

Question 983014: Complete the square on both the x and y terms to rewrite the equation 2x^2−3y^2−4x+12y−22 = 0 so that you can use the rewritten equation to relate this equation to a particular conic section. Then sketch its graph.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2-4x-3y%5E2%2B12y=22
2%28x%5E2-2x%29-3%28y%5E2-4y%29=22
2%28x%5E2-2x%2B1%29-1%2F2-3%28y%5E2-4y%2B4%29%2B12=22
2%28x-1%29%5E2-3%28y-2%29%5E2-1%2F2%2B12=22
2%28x-1%29%5E2-3%28y-2%29%5E2=22-12%2B1%2F2
2%28x-1%29%5E2-3%28y-2%29%5E2=10%261%2F2
2%28x-1%29%5E2-3%28y-2%29%5E2=21%2F2
%284%2F21%29%28x-1%29%5E2-%286%2F21%29%28y-2%29%5E2=1
highlight%28%28x-1%29%5E2%2F%2821%2F4%29-%28y-2%29%5E2%2F%2821%2F6%29=1%29

To begin what is the meaning, hyperbola with center (1,2), axis joining the vertices is vertical.