SOLUTION: Write the equation of the line with the given conditions Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16 A) y=-3/2x+9/2 B) y=-2/3x-2/3 C)

Algebra ->  Graphs -> SOLUTION: Write the equation of the line with the given conditions Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16 A) y=-3/2x+9/2 B) y=-2/3x-2/3 C)       Log On


   

Question 980930: Write the equation of the line with the given conditions
Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16
A) y=-3/2x+9/2
B) y=-2/3x-2/3
C) y=-1/3x+16/3
D) y=3/2x+9/2
Found 3 solutions by josgarithmetic, MathTherapy, solver91311:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Any line perpendicular to -2x%2B3y=-16 would be some 3x%2B2y=c; and if this line contains or passes through (1,-6), then 3x%2B2y=3%2A1%2B2%28-6%29, or 3x%2B2y=-9.

To find the correct choice, solve the resulting equation for y.

Understanding Standard Form Equation for a line is very helpful.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Write the equation of the line with the given conditions
Passing through (1,-6) and perpendicular to the line with equation -2x+3y=-16
A) y=-3/2x+9/2
B) y=-2/3x-2/3
C) y=-1/3x+16/3
D) y=3/2x+9/2
- 2x + 3y = - 16

3y = 2x - 16

y+=+%282%2F3%29x+-+16%2F3

m+=+-+1%2F%282%2F3%29, or m+=+-+3%2F2 

With m+=+-+3%2F2, and point (1, - 6), we get: 

y+-+-+6+=+-+%283%2F2%29%28x+-+1%29 

y+%2B+6+=+-+%283%2F2%29x+%2B+3%2F2

y+=+-+%283%2F2%29x+%2B+3%2F2+-+6

highlight_green%28y+=+-+%283%2F2%29x+-+9%2F2%29 <--------- NONE OF THE CHOICES

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Perpendicular lines have slopes that are negative reciprocals. Put the given equation into slope-intercept form, find the slope of the given line, then take the negative reciprocal of that slope. Since the four given answers all have different slopes, you don't need to bother finding the intercept for the desired equation.

John

My calculator said it, I believe it, that settles it