SOLUTION: f(x) = -9x2 + 2x + 4. I am having trouble finding an aproximate value for f(x)=0

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Question 972857: f(x) = -9x2 + 2x + 4. I am having trouble finding an aproximate value for f(x)=0
Found 2 solutions by Boreal, solver91311:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
-9x^2 +2x +4 =0
change all signs to make the square term positive. It is much easier.
9x^2 - 2x - 4=0
quadratic formula
(1/18) [ 2 +/- sqrt (4+144)] a=9 b=-2 4ac=4*(-4)*9
(1/18) 2+/- sqrt (148) ;;sqrt 148=12.17
(2+12.17)/18
14.17/18=0.787
(2-12.17)/18
-10.17/18= - 0.565
Approximate values are -0.565,+0.787
graph+%28300%2C300%2C-5%2C5%2C-5%2C5%2C-9x%5E2%2B2x%2B4%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The value of when is exactly . But I'm going to go out on a limb here and guess that you really meant to ask about the values of such that .

Your little bit of ugliness doesn't factor, so your choices are to complete the square (if you are some sort of glutton for punishment) or use the quadratic formula.



Where

, , and

Plug in the numbers and do the arithmetic to find your two values.

By the way, use a caret ("^") mark to indicate raising to a power in plain text. -9x^2 + 2x + 4 means whereas -9x2 + 2x + 4 is just goobledygook.

John

My calculator said it, I believe it, that settles it