SOLUTION: given that x^2+2x+1>0 , can i say that x^2+2x+1 is the y values of the graph?

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Question 967790: given that x^2+2x+1>0 , can i say that x^2+2x+1 is the y values of the graph?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
your equation is x^2 + 2x + 1 > 0

if you set your equation to y, then the equation becomes:

y = x^2 + 2x + 1

if x^2 + 2x + 1 > 0, then y > 0 as well because y = x^2 + 2x + 1.

you would graph y = x^2 + 2x + 1.

you would look for all values of y that are > 0.

the graph of your equation looks like this:

graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E2+%2B+2x+%2B+1%29

your graph touches the x-axis at x = -1.

that means that y = 0 when x = -1.

the solution to x^2 + 2x + 1 > 0 is all values of x except at x = -1.

this means that y > 0 at all values of x except at x = -1, because y = x^2 + 2x + 1.